sistem persamaan berkut akan diselesaikan menggunakan eleminasi gaus
2X1 + X2 + 3X3 = 11
4X1 + 3X2 + 10X3 = 28
2X1 + 4X2 + 17X3 = 31
2X3 = 2
X3 = 1
X2 + 4X3 = 6
X2 + (4 * 1) = 6
X2 = 6 – 4 = 2
2X1 + X2 + 3X3 = 11
2X1 + (1 * 2 ) + (3 * 1) = 11
2X1 = 11 – 2 – 3 =6
X1 = 3
Pembuktian
4X1 + 3X2 + 10X3 = 28
(4 * 3) + (3 * 2) + (10 * 1) = 28
12 + 6 + 10 =28
28 = 28
Pusing bro . . .
BalasHapus